I was wondering, though, if the Stat Exp. variable could also be reduced to decrease Attack even lower, and by how much?

Obviously, it would be easy to Shark those values all the way down to 0. However, my goal was to find the lowest LEGAL value that Attack could have while all other stats were maxed.

It was a problem that I was working on for two whole days, and even now it still has a slight bit of incompletion. Here is my research.

To get the low Attack, you want to battle Pokemon whose base Attack stats are as low as possible, to limit the Stat Exp. received in Attack. For a start, before battling at all, I use 10 stat drugs of every variety except Protein, so the other Stat Exp. values start at 25600. To max out stats, those values must all be at least 16 (63²) – 8 (63) + 2 = 63002.

Best ratios of base stats in each stat vs. Attack:
HP: 50, Chansey
Defense: 23, Shuckle
Special A: 7.5, Blissey (Chansey close behind at 7.0)
Special D: 23, Shuckle
Speed: 10, Chansey

So trying to find a solution using only Chanseys and Shuckles seems reasonable. There are five equations that must be considered to find the optimum solution:

250a + 20b ≥ 37402
5a + 230b ≥ 37402
35a + 5b ≥ 37402
105a + 230b ≥ 37402
50a + 10b ≥ 37402

The optimum solution is the one involving integral values for a and b that produces the smallest value for 5a + 10b. After graphing everything out, I found the best solution. You would have to battle 140 Shuckles and 1049 Chanseys, giving Stat Exp. for Attack of 6645 (HEX 19F5). Plugging 6645 into int(((√ (V – 1) + 1) / 4), this value adds just 20 points to your Attack score. (Yes, I know that Blissey has a better Special-A-to-Attack ratio, and that this might improve it. However, ignoring the “int” command in the above equation, we get 20.6292..., and I doubt it would improve on that enough to knock it below 20.)

The one piece of missing research is: Since there are only 5 areas to enter Stat Exp., how does that work with two Special stats? If Special Stat Exp. is transferred from Special A, the above solution is still best. If, however, it transfers from Special D, the third equation is removed. That equation was easily the most influential in jacking up the totals. Without it, the optimum solution is 149 Shuckles and 719 Chanseys, giving Attack Stat Exp. of 5085 (HEX 13DD). That reduces the value of int(((√ (V – 1) + 1) / 4) down to 18. With the third equation removed, EVERY other “(Stat) vs. Attack” ratio has either Shuckle or Chansey as most efficient, so this solution cannot be bettered.

So I’m looking to know how Special stats transfer Stat Exp.: through SA or SD? If it is through SA, there may be some additional research involved. A TI-83 can’t do 3-D graphs, so I’d need someone else’s help to test a three-variable system, adding Blissey. Does that improve the solution for “5a + 10b + 10c” at all?

In conclusion, you can legally do more than just a 1 Attack DV for reducing Attack. If you want the minimum that can be attained legally, right now I know you can reduce Attack’s Stat Exp. variables (DA37 and DA38) down at least as far as 19 F5 (for those of you who shark “only legal things,” I see nothing wrong with doing this). And if Special Stat Exp. is found to transfer from Special D, you can knock it down to 13 DD and shave off ANOTHER two points.

But I doubt anyone will pay much attention to this, so I just wasted 2 days on a pointless discovery...

So if you're sharking Attack to the minimum legally possible, just set DA37 to 19 and DA38 to F5 at least for now). "cmsnrub25" gets a 5.

Now, the final piece: Does anyone care to test to see if adding Blissey to the mix will enable the Attack to go any lower (because of its higher Special-A-to-Attack ratio)? I don't have the tools to check a 3-D system of equations, but maybe someone else might--if anyone cares to try it, it's a 5-star rating to whoever figures it out!

I'm not a 3D-graph expert, but if you could supply me with the expression necessary to draw the graph you want, then I'd be happy to help.

No?

Well, you still get a 5, Jolt.

250x + 20y + 255z ≥ 37402

5x + 230y + 10z ≥ 37402

35x + 5y + 75z ≥ 37402

105x + 230y + 140z ≥ 37402

50x + 10y + 55z ≥ 37402

with the object being the solution involving only integer values that gives the lowest possible value for 5x + 10y + 10z. x is obviously the number of Chanseys, y is Shuckles, and z is Blisseys. The current best solution, involving only Chansey and Shuckle, is 6645, but unless the new solution goes below 6242 (the breaking point between 19 and 20 in the Stat Exp. reverse equation), it will be of no additional value.

Solving these equations for z gives:

z ≥ (37402 – 250x – 20y) / 255

z ≥ (37402 – 5x – 230y) / 10

z ≥ (37402 – 35x – 5y) / 75

z ≥ (37402 – 105x – 230y) / 140

z ≥ (37402 – 50x – 10y) / 55

Hope these help.

quote:

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Originally posted by Jolt135:
I think you need to re-read the first post. It says 1049 Chanseys, not 1041. That boosts up Attack SE by 8 * 5 = 40 points, which puts it at the 6645 I mentioned.

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quote:

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Originally posted by Jolt135:
Lark84: The equations I would need fulfilled are:
(equations posted by Jolt135)

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*tries to plug in first equation into graphing program*

*finds out program can't use the *-sign*

*replaces * with =*

*gets a nice, flat, tilted surface, exactly like the surface you get from z=x*

I'm sorry my program couldn't use the *-sign, but as I said, it's very basic (it comes included with system software, guess that says pretty much about the capabilities of it ). I'm not sure if my completely flat graph is of any use to you... You get the exact same result with z=x, or z=y. Sorry...

Even with Special SE transferring from Special A, and even without Blissey, I just remembered a loophole that allows the solution to improve from 19F5.

Recall that in RBY, there was only one Special, and Chansey’s Base Stat there was still 105. However, in GSC, this gets shot all the way down to 35, making it take three times longer to max out Special Attack SE with Chansey.

Therefore, why use GSC for that? After taking down the Shuckles (don’t worry about Shuckle’s 230 Special D Base Stat getting erased and only the 5 remaining; the 230 never gets added to SE in the first place) the theoretical solution would have the Pokemon traded back to RBY so it can get 105 Special SE off Chansey instead of 35! When the requisite number of Chanseys are taken down, trading back to GSC keeps the 105-per-Chansey Special SE.

As far as the implications on the optimum solution, this makes Equation 3 much easier to fulfill. Because of this, fighting Blissey wouldn’t improve on anything (sorry, Lark84, for wasting your time). The best solution now is 149 Shuckles and 719 Chanseys, giving Attack SE of just 13DD (worth 18 stat points), which is exactly what it would be if Equation 3 had been removed altogether.

If anyone else finds a potential loophole in the research, post it here.